chess: (Default)
Gah, evil maths.

I have:
L=2r*sin(l/2r) (that's a small L, not a 1)
h=r(1-cos(l/2r)) (before the cos is a 1, after is a small L)
I know L and l, and I want h in terms of these.

*mutters about nasty Engineering projects and people who are meant to be helping who don't have email at home*

Date: 2002-03-16 09:07 am (UTC)From: [identity profile] stipe.livejournal.com
It's been too long since I did any of this stuff, but my guess is that 2sin(x)/(1-cos(x)), or some rearrangement thereof, is an identity and can be simplified.

Re:

Date: 2002-03-17 10:04 am (UTC)From: [identity profile] naath.livejournal.com
possibly... I can't remember anything of that form though.

Date: 2002-03-20 08:36 am (UTC)From: [identity profile] passage.livejournal.com
sin(x)=2sin(x/2)cos(x/2)
1-cos(x)=2sin^2(x/2)
=> 2sin(x)/(1-cos(x))=2cot(x/2)

I don't think this helps however ...

Neil

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Michelle Taylor

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